; GEUP3D?im5Xc"ArialvBI#. N` BS{\rtf1\ansi\ansicpg1252\deff0\deflang3082{\fonttbl{\f0\fnil\fcharset0 Arial;}{\f1\fnil\fcharset0 MS Sans Serif;}} {\colortbl ;\red0\green0\blue0;} \viewkind4\uc1\pard\cf1\i\fs20 A2. Toda recta que forma \'e1ngulos iguales con otras tres que pasan por su pie en un plano, es perpendicular a dicho plano.\i0 \cf0\f1\fs17 \par } 'OvA'?I'u9 'bx0[\$'r3vA'?I'u9 bx0[\'0жrc?$'r2vA'?I'u9 0жrc?'I0͋:gb!$'r1vA'?I'u9 I0͋:gb!B'0жrc?I0͋:gb!bx0[\k' vA'?I'u9 vA'?I'u9 , P vA'?I'u9 5 @5 RR88, R2"f2/k(/QF@IA@/'@  z+ R3 P{6ӟ<$z+  Wd@J@z+ kti /}&z+R1 #V=H@J8^@'@ #V=H@J8^@vA'?I'u9 5 @'@ "f2/k(vA'?I'u9 5 @'@ vA'?I'u9 5 @P{6ӟ<$<(P 8"ArialvBI(ّA(E"ArialvBI!vA'?F(f"ArialvBIh"I'u9 K("ArialvBI#5 @)PR1 =  :"ArialvBI ,(3M~(@)PR2 =  "ArialvBI,(3M~(@)PR3 =  "ArialvBIP-)3M~(@)@POR1 =  T"ArialvBI-@V@)@POR2 =   R"ArialvBI.@V@)@POR3 =   R"ArialvBI/@V@['@ S?mS?m?&?` ,@Q{$kٿD@@D@@KV)@@ QOR1 = '"ArialvBIH0@@K U@)@@!QOR2 =  "ArialvBI0@@^wE,Y@)@@"QOR3 =  "ArialvBIx1@@K U@'#vA'?I'u9 {$kٿD@@'$ "f2/k({$kٿD@@'%{$kٿD@@#V=H@J8^@'& {$kٿD@@P{6ӟ<$<('Q"ArialvBIّA(('"ArialvBI2{F()'"ArialvBI2$kٿK(*' "ArialvBI@3D@@ N+`[0!A{\rtf1\ansi\ansicpg1252\deff0\deflang3082{\fonttbl{\f0\fnil\fcharset0 Arial;}{\f1\fnil\fcharset0 MS Sans Serif;}} {\colortbl ;\red0\green0\blue0;} \viewkind4\uc1\pard\cf1\fs20 Los \'e1ngulos ser\'e1n iguales a 90\'ba\cf0\f1\fs17 \par } N,`;nP{\rtf1\ansi\ansicpg1252\deff0\deflang3082{\fonttbl{\f0\fnil\fcharset0 Arial;}{\f1\fnil\fcharset0 MS Sans Serif;}} {\colortbl ;\red128\green0\blue0;} \viewkind4\uc1\pard\cf1\b\i\fs20 1\'aa \b0 SOLUCI\'d3N: \par Para facilitar la comprobaci\'f3n hemos situado \par el punto Q en el plano mediador de R1 y R3.\cf0\f1\fs17 \par } N-`FH{\rtf1\ansi\ansicpg1252\deff0\deflang3082{\fonttbl{\f0\fswiss\fcharset0 Arial;}} {\colortbl ;\red0\green0\blue0;} \viewkind4\uc1\pard\cf1\i\f0\fs20 Mover Q y situarlo lo m\'e1s pr\'f3ximo a P \par }